3-SAT → Variable-alphabet lettericity Complexity open
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Why this question matters
This addresses recognition when the alphabet is an input parameter, beyond fixed-alphabet structural results.
Fixed-alphabet algorithms and supplied-partition formulations do not classify recognition when both the alphabet budget and the partition are part of the problem.
The reduction to construct
A source instance is an explicitly encoded Boolean formula with at most three literals per clause. Its outputs are satisfying Boolean assignments, or NO-SOLUTION when the formula is unsatisfiable.
Given a graph G and alphabet budget k, find a vertex order, a letter for every vertex, and a directed decoder on at most k letters such that each earlier/later vertex pair is adjacent exactly when its ordered letter pair is in the decoder.
Construct deterministic polynomial-time maps F and G: F sends every legal source instance to a legal target instance, and G(x,y) is a valid source output for every valid output y of F(x). Preserve the stated threshold, domain and promises. The requested complexity conclusion is NP-hardness for the stated target problem.
Both the order and the partition are free. A hard-looking encoding with a supplied partition need not prove the unrestricted result.
What a complete answer must include
Give explicit construction and recovery algorithms, a general proof for every legal input and every valid target output, and polynomial runtime and encoding-size bounds. Specify finite output encodings and handle NO-SOLUTION outputs when applicable. Tests compare recovered source outputs with independent source solutions.
References
- Section 6 ↗
- arXiv:2605.07899v1 ↗
- arXiv record ↗
- 10.1007/978-3-032-31348-5_20 ↗
- Cycles in Unions of Transitive Tournaments ↗
Literature checked 2026-09-16. This summarizes the archived literature search on the date above. Unpublished, unindexed and overlooked work remains outside coverage; no new novelty assessment was performed.